Simple if statement in C

Simple if Syntax

The form of an if statement is as follows:

Practice Programs

(i)	   
#include<stdio.h>
void main()
{
	system("color fc"); 
	// e = = light yellow = Output window background color
	//c = = Light red = Output window text color 
	int x = 5;
	
	if(x)
	printf("EngineersTutor.com")
}

(ii)
#include<stdio.h>
void main()
{
	system("color ec"); 
	// e = = light yellow = Output window background color
	//c = = Light red = Output window text color 
	
	int x = 5;
	
	if(x>10)
	printf("EngineersTutor.com");
}

(iii)
#include<stdio.h>
void main()
{
	system("color ec"); 
	// e = = light yellow = Output window background color
	//c = = Light red = Output window text color
	
	int x = 5;
	
	if(x == 10)
	printf("EngineersTutor.com");
}

(iv)
#include<stdio.h>
void main()
{
	system("color ec"); 
	// e = = light yellow = Output window background color
	//c = = Light red = Output window text color
	
	int x = 5, y = 10;
	
	if(x+y)
	printf("EngineersTutor.com");
}

(v)
#include<stdio.h>
void main()
{
	system("color ec"); 
	// e = = light yellow = Output window background color
	//c = = Light red = Output window text color
	
	int x = 5, y = 10;
	
	if( (x+y)>30 )
	printf("EngineersTutor.com");
}

(vi)
#include<stdio.h>

void main()
{
	system("color ec"); 
	// e = = light yellow = Output window background color
	//c = = Light red = Output window text color
	
	int x = 5, y = 10;
	
	if( (x+y)>30 )
	{
		printf("EngineersTutor.com");
		printf("Teach Easy");
	}
}

(vii)
#include<stdio.h>
void main()
{
	system("color ec"); 
	// e = = light yellow = Output window background color
	//c = = Light red = Output window text color
	
	int x = 5, y = 10;
	
	if( (x+y)<30 )
		printf("EngineersTutor.com\n");
		printf("Teach Easy\n");
	    printf("Albert\n");
	    printf("Stephen");
}

(viii) Testing for Leap year
#include<stdio.h>

void main()
{
	int year;
	printf("enter year \n");
	scanf("%d", &year);
	
	if((year%400==0)||((year%4==0)&&(year%100!=0)))
		printf("given year is leap year \n");	
	else
		printf("not leap year \n");
}

Program explanation