Simple if – else statement in C++

Simple if – else Syntax
The form of an if statement is as follows:

Note that every operator in C++ must return some value. For example, + operator returns sum of two numbers, * operator return multiplication of two numbers etc.

Practice Programs

(i)	   
#include<iostream>
using namespace std;

int main()
{
	int x = 5;
	
	if(x)
	cout<<"Stephen Hawking";
	else
	cout<<"Albert Einstein";
	
	return 0;
}

(ii)
#include<iostream>
using namespace std;

int main()
{
	int x = 5;
	
	if(x>10)
	cout<<"Stephen Hawking";
	else
	cout<<"Albert Einstein";
	
	return 0;
}

(iii)
#include<iostream>
using namespace std;

int main()
{
	int x = 5;
	
	if(x == 10)
	cout<<"Stephen Hawking";
	else
	cout<<"Albert Einstein";
	
	return 0;
}

(iv)
#include<iostream>
using namespace std;

int main()
{
	int x = 5, y = 10;
	
	if(x+y)
	cout<<"Stephen Hawking";
	else
	cout<<"Albert Einstein";
	
	return 0;
}

(v)
#include<iostream>
using namespace std;

int main()
{
	int x = 5, y = 10;
	
	if( (x+y)>30 )
	cout<<"Stephen Hawking";
	else
	cout<<"Albert Einstein";
	
	return 0;
}

(vi)
#include<iostream>
using namespace std;

int main()
{
	int x = 5, y = 10;
	
	if( (x+y)>30 )
	{
		cout<<"Stephen Hawking"<<endl;
		cout<<"Cosmology";
	}
	
	else
	{
		cout<<"Albert Einstein"<<endl;
		cout<<"Physics";
	}
	
	return 0;
}

(vii)
#include<iostream>
using namespace std;

int main()
{
	int x = 5, y = 10;
	
	if( (x+y)>30 )
		cout<<"Stephen Hawking"<<endl;
		cout<<"Cosmology";
	
	else
		cout<<"Albert Einstein"<<endl;
		cout<<"Physics";
	
	return 0;
}

(viii) Testing for Leap year
#include<iostream>
using namespace std;

int main()
{
	int year;
	cout<<"enter year";
	cin>>year;
	
if((year%400==0)||((year%4==0)&&(year%100!=0)))

cout<<"given year is leap year";
else
cout<<"not leap year";
return 0;
}